
Two families trade in their vehicles for more fuel-efficient ones. If both travel the same amount each year, which will save more fuel by making the change?
Family 1 decides to trade in their 4-wheel drive Jeep Patriot (25.5 avg. MPG) for a Civic Hybrid (42.5 avg. MPG).
Family 2 decides to trade in their 4-wheel drive Chevy Trailblazer (14 avg. MPG) for a 4-wheel drive Jeep Patriot (25.5 avg. MPG).
Please vote before continuing if you don’t want to cheat.
[poll id="22"]
Did most of you think Family 1?
Well . . . that is wrong by a long shot. In fact, Family 2 will save more than twice as much fuel as Family 1! The problem here, however, is not you – it is the poor metric of MPG (miles per gallon).
If you don’t believe us, let’s do the math. Assume both families drive 10,000 miles per year.
Family 1 goes from buying 392 gallons of gas per year (10,000 miles / 25.5 MPG) to buying 235 gallons of gas per year (10,000 miles / 42.5 MPG) — resulting in an annual fuel savings of 157 gallons.
Family 2 goes from buying 714 gallons of gas per year (10,000 miles / 14 MPG) to buying 392 gallons of gas per year (10,000 miles / 25.5 MPG) — resulting in annual fuel savings of 322 gallons – or more than twice as many gallons as Family 1.
What does this mean to the Postal Service? The best way the Postal Service (or any organization for that matter) can save fuel is to find the least efficient vehicles and replace them with modestly fuel efficient vehicles. Small changes can mean incredible savings. Use the math above to prove to yourself that raising a truck from 5 to 6 MPG will save more fuel than raising a car from 20 to 50 MPG! Also, prove to yourself that raising that truck from 5 to 10 MPG will save more than twice as much fuel as making a 20 MPG vehicle use no fuel whatsoever!!!
Do you have any ideas about how the Postal Service can use fuel more efficiently?
Comments (15)